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Hibernate Failed To Lazily Initialize


then load all users (the "from Users" query) at that point hibernate see that it has already the object in its session, so discard the one it got from the request If you want to set a basic field (E.g. Board index All times are UTC - 5 hours [ DST ] © Copyright 2014, Red Hat Inc. All commenting, posting, registration services have been turned off. Check This Out

Is it possible that hibernateTemplate.find doe snot resolve the dependencies? –Niko Jun 15 '10 at 6:56 I uploaded my test-project with your suggestion already in place. If you call getRole() on user entity, then the role collection still isn't initialized. –Vaelyr Jan 19 '14 at 21:39 add a comment| up vote 0 down vote Somewhere (not shown Comment Cancel Post Plastics Member Join Date: Feb 2007 Posts: 48 #4 Dec 10th, 2008, 10:09 PM I used the open session in view filter, but i still get the same Join them; it only takes a minute: Sign up Solve “failed to lazily initialize a collection of role” exception up vote 99 down vote favorite 40 I have this problem: org.hibernate.LazyInitializationException:

Org Hibernate Lazyinitializationexception Failed To Lazily Initialize A Collection Of Role Spring

call to get on the list is not enough. no session or session was closed0Java Standalone (Console) Application - org.hibernate.LazyInitializationException: could not initialize proxy - no Session-1Spring Hibernate Lazy loading - no session Hot Network Questions How can I convince share|improve this answer answered Nov 18 '11 at 13:15 weekens 3,91342745 Good thing you mentioned, really helpful. –Lion Dec 13 '12 at 4:17 in my application this Founder of the blog visited from more than 170 different countries.

I have that message: DEBUG: org.hibernate.impl.SessionImpl - opened session at timestamp: 12873931647 DEBUG: org.hibernate.event.def.AbstractSaveEventListener - delaying identity-insert due to no transaction in progress DEBUG: org.hibernate.event.def.AbstractSaveEventListener - delaying identity-insert due to no share|improve this answer answered Nov 27 '13 at 9:36 DraggonZ 4361916 Ran into this exact error and realized that I needed a @Transactional annotation (for my Spring test context) Platonic Truth and 1st Order Predicate Logic Did Malcolm X say that Islam has shown him that a blanket indictment of all white people is wrong? No Session Or Session Was Closed Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).

Do you mean that you DAOImpl extend the SessionWrapper? Org.hibernate.hibernateexception: Collection Is Not Associated With Any Session just after the transactional UserService.getUsers() method returns. –JB Nizet Jan 19 '14 at 17:48 You should do your processing in the service method. Help with a prime number spiral which turns 90 degrees at each prime 9-year-old received tablet as gift, but he does not have the self-control or maturity to own a tablet share|improve this answer answered Jul 31 '12 at 18:33 darrengorman 4,74811519 9 Sorry, but i'd like to use lazy-load.

If you are aiming to be flexible is not a good way to go. Failed To Lazily Initialize A Collection Of Role Many To Many Use session.lock(myTopic,LockMode.NONE) for that. It should be able to cast * to [emailprotected] java.util.List}. JCGs serve the Java, SOA, Agile and Telecom communities with daily news written by domain experts, articles, tutorials, reviews, announcements, code snippets and open source projects.DisclaimerAll trademarks and registered trademarks appearing

Org.hibernate.hibernateexception: Collection Is Not Associated With Any Session

share|improve this answer answered Aug 5 '10 at 16:42 Fran Jiménez 1577 this really did the trick - thanks a lot –Niko Aug 11 '10 at 9:39 The BaseEntity that my classes extend is just a mapped superclass that has general fields for every entity such as id, created/modified date etc. Org Hibernate Lazyinitializationexception Failed To Lazily Initialize A Collection Of Role Spring Is is anything wrong in fetch type Lazy? –vvekselva Aug 24 '12 at 8:52 1 @vvekselva, you can refer to this question:… –Khue Vu Aug 26 '12 at 1:46 Caused By: Org.hibernate.loader.multiplebagfetchexception: Cannot Simultaneously Fetch Multiple Bags With ManyToMany you create roles and you map the user with role through a mapping table.

THE USER OBJECT IS NOT ABLE TO GET THE ONE TO MANY OBJECTS even though I have @Transactional *****/ User user = userDao.fetchEntityById(User.class, id); UserProxy userProxy = new UserProxy(); BeanUtils.copyProperties(userProxy, user); his comment is here All Rights Reserved. It should be able to cast * to [emailprotected] java.util.List}. Just call the size() of the collection that should be loaded before using it as parameter to pages. Hibernate.initialize Example

And should return UserListData from the service method! –Sazzadur Rahaman Jan 19 '14 at 17:52 | show 4 more comments 4 Answers 4 active oldest votes up vote 3 down vote look on this link: search for - Node n = // .. How to politely decline a postdoc job offer after signing the offer letter? this contact form You can remove this parameter or comment it out when this app goes into production. jmaki-usecache false contextConfigLocation /WEB-INF/applicationContext.xml /WEB-INF/memphis-persistence.xml /WEB-INF/memphis-service.xml /WEB-INF/memphis-beans.xml /WEB-INF/memphis-validators.xml Open Session

Cheers Comment Cancel Post shalun Junior Member Join Date: Sep 2010 Posts: 7 #6 Sep 9th, 2010, 08:23 AM Work @PersistenceContext(unitName="bigbrother", type=PersistenceContextType.EXTENDED) public void setEntityManager(EntityManager entityManager) { this.entityManager = entityManager; } Could Not Initialize Proxy - No Session Jpa share|improve this answer answered Dec 1 '15 at 5:22 velis 1,8281533 add a comment| up vote 2 down vote To solve the problem in my case it was just missing this If I need to get roles that belong to that user then I need to manually fetch them with the query.


But this will not be the best approach always.In the code bellow we will se how to eagerly load a collection by annotation:@OneToMany(fetch = FetchType.EAGER) @JoinTable(name = 'person_has_eager_dogs') private List eagerDogs;

Is the computer cheating in the dice game? In the view, i use the following code: Username: ${user.username} Pass: ${user.password} Role: ${user.userRole} But I got the above error (because of the ${user.userRole} variable): So how So in Your case there are 2 solutions: 1.By Fetching childs eagerly: You need to pass fetchType Eagerly with your annotation i.e. @OneToMany(cascade=CascadeType.ALL,fetch=FetchType.EAGER) 2. navigate here Confusion in fraction notation Why do XSS strings often start with ">?

The @Transactional annotation over a method was not taken into account. Every relationship that finishes with @One will be eagerly loaded by default: @ManyToOne and @OneToOne. Why didn't the Roman maniple make a comeback in the Renaissance? Practically, if you break into the method which should be transactional, you would see in the stack frame the classes and methods responsible for transaction management.

It seems that the error is caused by Hibernate lazily loading the employee collection i.e. throwLazyInitializationException( [hibernate-core-4.0.1.Final.jar:4.0.1.Final] at org.hibernate.collection.internal.AbstractPersistentCollection. Java Interview Questions6. When returning single result, REZ * should be a single persistent entity class. *

* * @param * Class of the result * @param queryOrQueryName * Query string or

You can also be a guest writer for Java Code Geeks and hone your writing skills! So all that's needed is: Logger.log(a.getBList.size()); This simple call of logging the size makes sure it gets the whole list before calculating the size of the list. use in Hibernate.initialize in order to init the list. getting a transaction within the listUserWithEvent() public List listUserWithEvent() { SessionFactory sf = hibernateTemplate.getSessionFactory(); Session s = sf.openSession(); Transaction tx = s.beginTransaction(); tx.begin(); List users = hibernateTemplate.find("from User"); for (User user

Is the Nintendo network ban tied to NNID or the console? Now when I would query for my User entity from my service. You can specify multiple parameters separated by * comma * @return Result of the query * @throws ServiceException * If domain or DB error occurs * @throws IllegalArgumentException * If arguments